n, m = map(int, input().split())
a = [int(x) for x in input().split()]
b = [int(x) for x in input().split()]
def func(m, n):
for j in range(m, n):
if a[j] == 1 and b[j] == 1:
return "YES"
return "NO"
if a[0] == 1:
if a[m - 1] == 1:
print("YES")
else:
if b[m - 1] == 1:
print(func(m, n))
else:
print("NO")
else:
print("NO") #include<bits/stdc++.h>
#define ll long long
using namespace std;
int main()
{
ios::sync_with_stdio(0);
cout.tie(0);
cin.tie(0);
int n, x; cin >> n >> x;
int track1[n];
int track2[n];
string result = "NO";
for(int i = 0; i < n; i++)
cin >> track1[i];
for(int i = 0; i < n; i++)
cin >> track2[i];
if(track1[0] == 1)
{
if(track1[x-1] == 1)
result = "YES";
else if(track2[x-1] == 1)
{
for(int i = x; i < n; i++)
{
if(track1[i] == 1 && track2[i] == 1)
{
result = "YES";
break;
}
}
}
}
cout << result << endl;
return 0;
}
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